Question

A Carnot air conditioner takes energy from the thermal energy of a room at 61°F and transfers it as heat to the outdoors, which is at 98°F. For each joule of electric energy required to operate the air conditioner, how many joules are removed from the room?

Answer 1

14.07 units of joules is removed for each joules of electricity used

Step-by-step explanation:

The heated room temperature
`T_(c)` = 61 °F

The outside temperature
`T_(h)` = 98 °F

For conversion from fahrenheit to kelvin we use the equation

(32°F − 32) × 5/9 + 273.15

`T_(c)` = 289.26

`T_(h)` = 309.82

For air conditioning,

COP =
`(T_(c) )/(T_(h) -T_(c) )`

COP =
`(289.26 )/(309.82 -289.26 )` = 14.07

This means that 14.07 units of joules is removed for each joules of electricity used