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Please answer this question now

Please answer this question now-example-1
User Gfoidl
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1 Answer

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Answer:

m∠C = 102°

Explanation:

The above diagram is a cyclic quadrilateral

Step 1

First we find m∠B

The sum of opposite angles in a cyclic quadrilateral is equal to 180°

m∠D + m∠B = 180°

m∠B = 180° - m∠D

m∠B = 180° - 80°

m∠B = 100°

Step 2

Since we have found m∠B

We can proceed to find the Angle outside to circle

m∠CDA = 2 × m∠B

m∠CDA = 2 × 100°

m∠CDA = 200°

m∠CDA = m∠CD + m∠DA

m∠DA = m∠CDA - m∠CD

m∠DA = 200° - 116°

m∠DA = 84°

Step 3

Find m∠DAB

m∠DAB = m∠DA + m∠AB

m∠DAB = 84° + 120°

m∠DAB = 204°

Step 4

Find m∠C

It you look at the cyclic quadrilateral properly,

m∠DAB is Opposite m∠C

Hence

m∠C = 1/2 × m∠DAB

m∠C = 1/2 × 204

m∠C = 102°

Therefore ,m∠C = 102°

User Nomi Ali
by
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