Question

The following reactions all have K < 1. 1) a. C6H5COO- (aq) + C6H5OH (aq) → C6H5COOH (aq) + C6H5O- (aq) b. F- (aq) + C6H5OH (aq) → C6H5O- (aq) + HF (aq) c. C6H5COOH (aq) + F- (aq) → HF (aq) + C6H5COO- (aq) Arrange the substances based on their relative acid strength.

Answer 1

the acid strength is the order of
`\mathsf{HF _((aq)) }` >
`\mathsf{C_6H_5COOH _((aq)) }` >
`\mathsf{C_6H_5OH _((aq)) }`

Step-by-step explanation:

Given that :

a .
`\mathsf{C_6H_5COO^- _((aq)) + C_6H_5OH _((aq)) \to C_6H_5COOH _((aq)) + C_6H_5O^- _((aq))}`

b.
`\mathsf{ F^- _((aq)) + C_6H_5OH _((aq)) \to C_6H_5O^- _((aq)) + HF _((aq)) }`

c.
`\mathsf{C_6H_5COOH _((aq)) + F^- _((aq)) \to HF _((aq)) + C_6H_5COO^- _((aq)) }`

Acid strength is the ability of an acid to dissociate into a proton and an anion. Take for instance.

HA ↔ H⁺ + A⁻

The acid strength of the following compounds above are:

`\mathsf{C_6H_5OH _((aq)) }` = 1.00 × 10⁻¹⁰

`\mathsf{HF _((aq)) }` = 6.6 × 10⁻⁴

`\mathsf{C_6H_5COOH _((aq)) }` = 6.3 × 10⁻⁵

As the acid dissociation constant increases the relative acid strength also increases.

From above, the acid strength is the order of
`\mathsf{HF _((aq)) }` >
`\mathsf{C_6H_5COOH _((aq)) }` >
`\mathsf{C_6H_5OH _((aq)) }`

`\mathsf{C_6H_5COO^- }`,
`\mathsf{C_6H_5O^- _((aq))}` and F⁻ are Bronsted- Lowry acid

Bronsted- Lowry acid are molecule or ion that have the ability to donate a proton.