Answer:
The score is

Explanation:
From the question we are told that
The population mean is

The standard deviation is

From the question we are told that the score follow a normal distribution
i.e

The proportion of score in the top 10% is mathematically

Where x is the minimum score required to be in the top 10%
Now the

So

So

So the critical value of 0.10 from the normal distribution table is

So

