Question

Suppose your weekly local lottery has a winning chance of 1/106. You buy lottery from them for x weeks in a row. What is the probability that you never win?

Answer 1

The probability mass function that you never win
`^xC_o` =
`((999999)/(1000000))^x`

Explanation:

Given that;

the winning chance of a weekly local lottery =
`(1)/(10^6)`

=
`(1)/(1000000)`

The probability of losing = 1 - probability of winning (winning chance)

The probability of losing =
`1- (1)/(1000000)`

The probability of losing =
`(999999)/(1000000)`

The probability mass function that you never win
`^xC_o` =
`((1)/(10^6) )^0 ( (999999)/(1000000))^x`

The probability mass function that you never win
`^xC_o` =
`((999999)/(1000000))^x`