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A line passes through the points (3,0) and (4,2). What is its equation in slope-intercept form?

User Ferrelwill
by
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1 Answer

7 votes

Answer:

y = 2x - 6

Explanation:

Slope intercept form:

Equation of the line:


\sf \boxed{ y = mx +b}

Here m is the slope and b is the y-intercept.

Step 1: Find the slope

(3 , 0) ⇒ x₁ = 3 & y₁ = 0

(4 , 2) ⇒ x₂ = 4 & y₂ = 2


\sf \boxed{Slope=(y_2-y_1)/(x_2-x_1)}


\sf = (2 -0)/(4-3)\\\\= (2)/(1)\\\\=2

m = 2

Step2: Now, substitute the value of 'm' in the equation.

y = 2x + b

Step3: In the above equation plug in any point. Here, (3 ,0) is chosed.

0 = 2*3 + b

0 = 6 + b

-6 = b

b = -6

Step4: Equation of the line:

y = 2x - 6

User Doug Steinberg
by
3.9k points