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2x.tg60= 10+csc30 plis

User Niv Apo
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1 Answer

3 votes

Answer:


2√(3)

Explanation:

I'm assuming the angles are in degrees.


2x \tan(60\º)=10+\csc(30\º)


$2x\cdot √(3)=10+(1)/(\sin(30\º)) $


$2x\cdot √(3)=10+(1)/((1)/(2) ) $


$2x\cdot √(3)=10+2} $


$x=(12)/(2√(3)) $


$x=(6)/(√(3)) =\frac{6√(3)} {3} }=2√(3) $

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