Question

A cylinder containing 14.71 L of helium gas at a pressure of 169.1 atm is to be used to fill toy balloons to a pressure of 1.086 atm. Each inflated balloon has a volume of 2.414 L. What is the maximum number of balloons that can be inflated? Report your answer to 1 decimal place. (Remember that 14.71 L of helium at 1.086 atm will remain in the exhausted (empty) cylinder)

Answer 1

The number of balloons is 948.8.

Step-by-step explanation:

The number of balloons can be calculated as follows:

`N = (V_(f))/(V_(T))`

Where:

`V_(f)`: is the volume at 1.086 atm

`V_(T)`: is the balloon volume = 2.414 L

The volume at 1.086 atm can be found using Boyle's law:

`P_(i)V_(i) = P_(f)V_(f)`

`V_(f) = (P_(i)V_(i))/(P_(f)) = (169.1 atm*14.71 L)/(1.086 atm) = 2290.5 L`

Now, the number of balloons is:

`N = (V_(f))/(V_(T)) = (2290.5 L)/(2.414 L) = 948.8`

Therefore, the number of balloons is 948.8.

I hope it helps you!