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Which value of x would make NO IKI

?
K
(x + 2) in
o 1
N
(x - 3) in
06
o 8
x-4) in 0
x in
o 10
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Which value of x would make NO IKI ? K (x + 2) in o 1 N (x - 3) in 06 o 8 x-4) in-example-1
User Morocklo
by
8.1k points

1 Answer

6 votes

Answer:


\boxed{x = 8}

Explanation:

For NO ║ KJ, The two triangles must be similar and their sides must be proportional.

So, the proportion of their sides is:

=>
(x-4)/(x) = (x-3)/(x+2)

Cross Multiplying


\sf x (x-3)= (x-4)(x+2)\\Multiplying\\x^2-3x = x^2+2x-4x-8\\x^2-3x = x^2-2x-8\\Subtracting\ x^2\ to \ both \ sides\\ -3x = -2x -8\\Adding \ 2x\ to\ both\ sides\\-3x+2x = -8\\-x = -8\\

x = 8

So, For x = 8, NO will be parallel to KJ.

User Hitokage
by
8.8k points
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