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The base of a regular pyramid is a hexagon.

The base of a regular pyramid is a hexagon.-example-1

1 Answer

3 votes

Answer:

96
√(3) cm²

Explanation:

A hexagon can be cut into 6 equilateral triangles.

Using the half shown in the diagram to calculate the apothem a , and the exact value

sin60° =
(√(3) )/(2) , then

sin60° =
(opposite)/(hypotenuse) =
(a)/(8) =
(√(3) )/(2) ( cross- multiply )

2a = 8
√(3) ( divide both sides by 2 )

a = 4
√(3) cm

The area (A) can be calculated using

A =
(1)/(2) pa ( p is the perimeter of the hexagon )

The sides of the hexagon measure 8 cm ( equilateral Δ has congruent sides )

p = 6 × 8 = 48 cm, so

A =
(1)/(2) × 48 × 4
√(3) = 96
√(3) cm²

User Fgakk
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