132k views
5 votes
The coefficient of x^ky^n-k in the expansion of (x+y)^n equals (nk). True or false.

2 Answers

6 votes

Answer:

True

Explanation:

apec

User Alexey Shikov
by
8.8k points
4 votes

Answer:

The correct option is;

False

Explanation:

The coefficient of x^k·y^(n-k) is nk, False

The kth coefficient of the binomial expansion, (x + y)ⁿ is
\dbinom{n}{k} = (n!)/(k!\cdot (n-k)!) = C(n,k)

Where;

k = r - 1

r = The term in the series

For an example the expansion of (x + y)⁵, we have;

(x + y)⁵ = x⁵ + 5·x⁴·y + 10·x³·y² + 10·x²·y³ + 5·x·y⁴ + y⁵

The third term, (k = 3) coefficient is 10 while n×k = 3×5 = 15

Therefore, the coefficient of x^k·y^(n-k) for the expansion (x + y)ⁿ =
C(n,k) not nk

User Iceydee
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories