Question

Bus drivers Andy, Benedict and Chris each return to Bus Terminal 1 every 50, 80, and 100 minutes respectively. If they leave the bus terminal at 0830 h, when will they next meet at the bus terminal ?​

Answer 1

1510 h, or 3:10 PM.

Explanation:

The next time they meet at the bus terminal will be a multiple of 50, 80, and 100.

A common factor among the three numbers is 10. If we divide all three by 10, we will get 5, 8, and 10. 5 is a factor of 10, so as long as 5 is multiplied by an even number, 10 will be a multiple.

Since the number will have to be divisible by both 5 and 8, the smallest possible number would be 5 * 8 = 40. So, the next time they meet at the bus terminal will be 40 * 10 = 400 minutes after 8:30.

400 minutes in hours is 400 / 60 = 40 / 6 = 20 / 3 = 6 hours and 2/3.

2/3 of an hour in minutes is (2/3) * 60 = 2 * 20 = 40.

So, they will meet again in 6 hours and 40 minutes.

8:30 plus 6 hours and 40 minutes is 14:70. 70 minutes translates into an hour and 10 minutes. So, the time will be 15:10, or 3:10 PM.

Hope this helps!