Question

What is the image of E for a 120° counterclockwise rotation about the center of the regular hexagon?

Answer 1

N

Explanation:

Since this hexagon has six sides, and to end up back at E again we’d need to rotate 360°, this means for every side we cross it’s a 60° turn.

Therefore,
`60 \cdot 2 = 120`° would be two sides.

Since we are moving counter-clockwise, the image for E would be to the left of it.

Two sides/points to the left of E is N, so the image of E for a 120° counterclockwise rotation around the center of this shape would be N.

Hope this helped!