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Find the angle θ between the two sides of a triangle whose lengths are 5cm and 4cm , if its area is 5cm²

User IHarshil
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\Delta = \frac 1 2 a b \sin C


\Delta=5, \quad a=5, \quad b=4


\sin C = (2 \Delta)/(ab) = (2 (5))/(5(4) ) = \frac 1 2


C=30^\circ \textrm{ or } C=150^\circ

Answer: two possibilities, θ=30° or 150°

User Ravidl
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