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Point A is at (6,-6) and point C is at (-6,-2). Find the coordinates of point B on line AC such that AB= 3/4 AC Urgent, need this immediately. PLS EXPLAIN

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(-3,0)..................
User Wwwuser
by
8.7k points
5 votes

Answer:


B(x,y) = (-3,0)

Explanation:

Given


A = (6,-6)


C = (-6,2)


AB = (3)/(4) AC

Required

Find coordinates of B

First, we need to convert
AB = (3)/(4) AC to ratio
AB:BC

SInce
AB = (3)/(4) AC, then


AB : BC = 3 : 4 - 3


AB : BC = 3 : 1

The coordinates of B can then be calculated as follows;


B(x,y) = ((nx_1 + mx_2)/(n + m),(ny_1 + my_2)/(n + m))

Where


A(x_1,y_1) = A(6,-6)


C(x_2,y_2) = A(-6,2)


m:n = 3 : 1

Substitute these values in the given formula;


B(x,y) = ((1 * 6 + 3 * -6)/(1 + 3),(1 * -6 + 3 * 2)/(1 + 3))


B(x,y) = ((6 -18)/(4),(-6 + 6)/(4))


B(x,y) = ((-12)/(4),(0)/(4))


B(x,y) = (-3,0)

Hence, the coordinates of B is
(-3,0)

User Xophmeister
by
7.9k points

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