Question

Solve application problems using radical equations. A hang glider dropped his cell phone from a height of 450 feet. How many seconds did it take for the cell phone to reach the ground?

Answer 1

`\large \boxed{\text{5.29 s}}`

Explanation:

The appropriate free fall equation is

y = v₀t + ½gt²

Data:

v₀ = 0

g = 32.17 ft·s⁻²

Calculation:

`\begin{array}{rcl}450 &=& v_(0)t + (1)/(2)gt^(2)\\\\& = & 0 * t + (1)/(2)* 32.17t^(2)\\\\& = & 16.08t^2\\t^(2)& = & (450)/(16.08)\\\\& = & 27.97\\t & = & \textbf{5.29 s}\\\end{array}\\\text{It took $\large \boxed{\textbf{5.29 s}}$ for the phone to reach the ground.}`