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Solve:
cos^2(2x)-sin^2(2x)=0 Thanks

User Ziggler
by
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1 Answer

3 votes

Answer:

x = pi/8 + pi/2 *n x = 3pi/8 + pi /2 *n

Explanation:

cos ^2 ( 2x) - sin ^2 (2x) = 0

Substitute u = 2x

cos ^2 ( u) - sin ^2 (u) = 0

We know cos ^2(x)-sin ^2(x)=cos (2x)

cos ( 2u) =0

Replacing u with 2x

cos (2 *2x) =0

cos (4x) =0

cos u =0 when u = pi/2 + 2 pi n and 3pi/2 + 2 pi n where n is an integer

4x = pi/2+2 pi n 4x = 3pi/2+2pi n

x = pi/8 + pi/2 *n x = 3pi/8 + pi /2 *n

User Lafi
by
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