Answer:
The answer is
x²y²( x + y)(x² - xy + y²)
Explanation:
![{x}^(5) {y}^(2) + {x}^(2) {y}^(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qlvf58zog374eblcnuyo3rh5tiexlzt21h.png)
To factorize the expression first factor
x²y² out
We have
x²y²( x³ + y³)
Using the expression
a³ + b³ = ( a + b)(a² - ab + b²)
Factorize the terms in the bracket
So we have
x³ + y³ = ( x + y)(x² - xy + y²)
Combine the expressions
We have the final answer as
x²y²( x + y)(x² - xy + y²)
Hope this helps you