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What is the area of this triangle on a Coordinate Grid?

Triangle IJK, with vertices I(3,-7), J(7,-4), and K(4,-2), is drawn inside a rectangle

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Answer: 8.5 sq. units.

Explanation:

Formula:

Area of triangle :
(1)/(2)|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|

Given: Triangle IJK, with vertices I(3,-7), J(7,-4), and K(4,-2)

Then, Area of triangle IJK =
(1)/(2)|3(-4-(-2))+7(-2-(-7))+4(-7-(-4))|


(1)/(2)|3(-2)+7(5)+4(-3)|\\\\=(1)/(2)|-6+35-12|\\\\=(1)/(2)(17)\\\\=8.5\text{ sq. units}

Hence, the area of this triangle IJK on a Coordinate Grid = 8.5 sq. units.

User Rakamakafo
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