Answer:
a. 30 meters per second
b. -10 meters per second
Explanation:
a. Average rate of change for the height from 0 to 6.6 secs can be calculated using the formula,
![m = (H(b) - H(a))/(b - a)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4zg4p04204uc7s0er1kwlrjwn0scehy0au.png)
Thus,
Where,
![a = 0, H(0) = 0](https://img.qammunity.org/2021/formulas/mathematics/high-school/7p7pgpy5flywew0rhs3egt9mif6o1ogt3o.png)
![b = 6.6, H(6.6) = 198](https://img.qammunity.org/2021/formulas/mathematics/high-school/tjizquh41pkmwnohd1uv6z00b4uv0iwizv.png)
Plug in the values into the formula:
![m = (198 - 0)/(6.6 - 0)](https://img.qammunity.org/2021/formulas/mathematics/high-school/iiq01ex6e5q3sgmb5lmwm6v532jil4yji4.png)
![m = (198)/(6.6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/tzmwmfvpxdhisrhklfp59ck2eg6pz5goh1.png)
![m = 30](https://img.qammunity.org/2021/formulas/physics/college/vz6z2rwzuocjf7355vkwubbkq5e5xtco5f.png)
b. Average rate of change for the height from 8.8 to 13.2 secs = tex] m = \frac{H(b) - H(a)}{b - a} [/tex]
Where,
![a = 8.8, H(8.8) = 44](https://img.qammunity.org/2021/formulas/mathematics/high-school/jtdc94u6surf05jei5j2xq52ycw8bwq7zo.png)
![b = 13.2, H(13.2) = 0](https://img.qammunity.org/2021/formulas/mathematics/high-school/y6qc0cfa09czick7gwpdva72dr2gdhnxfh.png)
Plug in the values:
![m = (0 - 44)/(13.2 - 8.8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/f4uvmf76psksrjhc0l7jyqpfkqsgp5bsjq.png)
![m = (-44)/(4.4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mh6kvis9s0s37do4e3bwyuwe4vx3n9gssc.png)
![m = -10](https://img.qammunity.org/2021/formulas/mathematics/high-school/qtjqrgr0vzdo7kzg9p1sumycevnjsol25z.png)