Question

On the coordinate plane below, Point P is located at (2,-3), and point Q is located at (-4,4).

Find the distance between points P and Q Round your answer to the nearest whole number.

Answer 1

Approximately 9 units.

Explanation:

To find the distance between two ordered pairs, we can use the distance formula. The distance formula is:

`d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2`

Let (2,-3) be x₁ and y₁ respectively, and let (-4,4) be x₂ and y₂, respectively.

`d=√((-4-2)^2+(4--3)^2) \\d=√((-6)^2+(7)^2) \\d=√(36+49) \\d=√(85)\approx9`