Question

Pls let me know what you get for this question

Answer 1

`h=13\,√(3)`

`x=52`

Explanation:

Using the triangle formed in the far left, we can use the Pythagorean theorem to solve for h:

`h^2+a^2=y^2\\h^2+39^2=(26\,√(3) )^2\\h^2=26^2\,(3)-39^2\\h^2=507\\h=√(507)\\h=13\,√(3)`

Now, using the right angle triangle on the right we solve for x:

`(x-a)^2+h^2=z^2\\(x-39)^2+507=26^2\\(x-39)^2=676-507\\(x-39)^2=169\\x-39=+/-13\\x=26\,\,\,or\,\,\,x=52`

since x has to be larger than "a" (39), we use the second answer:

`x=52`