63.7k views
3 votes
$i^{11} + i^{16} + i^{21} + i^{26} + i^{31}$
$i^(11) + i^(16) + i^(21) + i^(26) + i^(31)$

User Trikelef
by
5.6k points

1 Answer

3 votes

Answer:

Explanation:

i^{11}+i^{16}+i^{21}+i^{26}+i^{31}


=(i^(2) )^5i+(i^(2) )^8 +(i^(2) )^(10) i+(i^(2) )^(13)+(i^(2) )^(15) i\\=(-1)^5 i+(-1)^8+(-1)^(10) i+(-1)^(13) +(-1)^(15) i\\=- i+1+i-1-i\\=0- i

User Khalid Habib
by
5.2k points