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What is a3 if an=64(12)n−1
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What is a3 if an=64(12)n−1

User Dan King
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1 Answer

4 votes

Answer:


\huge\boxed{a_3=9,216}

Explanation:


a_n=64(12)^(n-1)\\\\\text{substitute}\ n=3:\\\\a_3=64(12)^(3-1)=64(12)^2=64(144)=9,216

User Dogcat
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