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A pickup truck has a width of 79.0 in. If it is traveling north at 42 m/s through a magnetic field with vertical component of

40 ut, what magnitude emf is induced between the driver and passenger sides of the truck?


User Komi Golov
by
8.9k points

1 Answer

0 votes

Answer:

The magnitude of the induced Emf is
0.003371V

Step-by-step explanation:

The width of the truck is given as 79inch but we need to convert to meter for consistency, then

The width= 79inch × 0.0254=2.0066 metres.

Now we can calculate the induced Emf using expresion below;

Then the
induced EMF= B L v

Where B= magnetic field component

L= width

V= velocity

=(40*10^-6) × (42) × (2.0066)

=0.003371V

Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V

User Andrew Roberts
by
8.3k points
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