Question

Easy khan academy math. please answer asap

Answer 1

`\boxed{\sf B \ and \ C}`

Explanation:

The triangle is a right triangle.

We can use trigonometric functions to solve.

`\sf sin(\theta)=(opposite)/(hypotenuse)`

`\sf sin(60)=(5.2)/(KL)`

`\sf KL=(5.2)/(sin(60))`

`\sf sin(90-60)=(3)/(KL)`

`\sf KL=(3)/(sin(90-60))`