Solve. 4(x+2)^2=16 HELP PLSSSS

HNSKD asked Feb 6, 2023

224,633 views

16 votes

Solve.
4(x+2)^2=16

HELP PLSSSS

HNSKD asked Feb 6, 2023

by HNSKD

2.4k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

17 votes

Answer:

x=0; x=-2

Explanation:

so first you do (x+2)^2 which is x^2+2x+4

4x^2 +8x +16 = 16

Subtract 16 from both sides

4x^2 +8x = 0

factor out 4x:

4x(x+2) = 0

Krishnan V S answered Feb 11, 2023

3.1k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers