Each triangular end has a surface area of (1/2)(base)(height), which in this case is (1/2)(4)(3), or 6 units^2. There are two ends, so the total area of the ends is 12 units^2. The three remaining sides account for the surface area
(4)(10) + (5)(10) + 3(10). or 120.
The sum of the surface areas of all five areas is 120 + 12 units^2, or 132 units^2
.Answer:
132 units^2