Question

5) A coil of wire consists of 20 turns, each of which has an area of 0.0015 m2. A magnetic field is perpendicular to the surface with a magnitude of B = 4.91 T/s t – 5.42 T/s2 t2. What is the magnitude of the induced emf in the coil?

Answer 1

The magnitude of the induced emf in the coil is 15.3 mV

Step-by-step explanation:

Given;

number of turns, N = 20 turns

Area of each coil, A = 0.0015 m²

initial magnitude of magnetic field at t₁, B₁ = 4.91 T/s

final magnitude of magnetic field at t₂, B₂ = 5.42 T/s

The magnitude of the induced emf in the coil is given by;

`E = -N(\delta \phi)/(\delta t) \\\\E =-N ((\delta B)/(\delta t) )A\\\\E = -NA((B_1-B_2))/(\delta t) \\\\E = NA((B_2-B_1))/(\delta t) \\\\E = 20(0.0015)(5.42-4.91)\\\\E = 0.0153 \ V\\\\E = 15.3 \ mV`

Therefore, the magnitude of the induced emf in the coil is 15.3 mV

Answer 2

1.5x10^-1 V

Step-by-step explanation:

See attached file