Answer:
The answer is "70 units".
Step-by-step explanation:
In the given question some equation is missing which can be defined as follows:
Monopolistic functions are used where Marginal Profit = Marginal Cost where marginal revenue and marginal cost stand for the MR and MC.
Finding the value of MR :



Calculating the value of the MC:


compare the above equation (i) and (ii):
