Question

The snowfall from this snowstorm above covered most of IA, northern IL, northern IN, and southern MI. While some locations in that swath saw over a foot of snow, let’s assume the average depth of the snow over this area was 8 inches. If the total area covered by the 8 inch average depth was 72,150 square miles, what percentage of the volume of the Grand Canyon would this amount of snow fill?

Answer 1

Percentage volume of the Grand Canyon filled by the snow = 0.911 %

Explanation:

This question is incomplete; please find the complete question in the attachment.

Given :

Area of the snow cover = 72150 square miles

Depth of the snow = 8 inches

Volume of the Grand Canyon = 4.166 × 101² m³

Solution:

Area of the snow cover = 72150 square miles

≈ 72150 × 2589988 square meter

≈ 1.868 × 10¹¹ square meter

Depth of the snow = 8 inches ≈ 0.2032 m

Volume of the snow on this area = Area × depth of the snow

= 1.868 × 10¹¹ × 0.2032

= 3.796 × 10¹⁰ m³

Volume of the Grand Canyon = 4.166 × 10¹² m³

Percentage volume of the Grand Canyon filled by the snow

=
`\frac{\text{Volume of the snow}}{\text{Volume of the Grand Canyon}}* 100`

=
`(3.796* 10^(10) )/(4.166* 10^(12) )* 100`

= 0.911%