Answer:
Step-by-step explanation:
For sound level in decibel scale the relation is
dB = 10 log I / I₀ where I₀ = 10⁻¹² and I is intensity of sound whose decibel scale is to be calculated .
Putting the given values
61 = 10 log I / 10⁻¹²
log I / 10⁻¹² = 6.1
I = 10⁻¹² x 10⁶°¹
![=10^(-5.9)](https://img.qammunity.org/2021/formulas/physics/college/j9dqfkbu79yvc1epq8y53m96wml2vhwgrd.png)
intensity of sound of 5 persons
![I=5* 10^(-5.9)](https://img.qammunity.org/2021/formulas/physics/college/t6zps72q8gasf5a1fb25qq87cqpb2lt0uu.png)
![dB=10log(5 X 10^(-5.9))/(10^(-12))](https://img.qammunity.org/2021/formulas/physics/college/s1af3irotx0b1fye4hwbokdr68r7979tf2.png)
= 10log 5 x 10⁶°¹
= 10( 6.1 + log 5 )
= 67.98
sound level will be 67.98 dB .