Question

A chemist adds of a M sodium carbonate solution to a reaction flask. Calculate the millimoles of sodium carbonate the chemist has added to the flask. Round your answer to significant digits.

Answer 1

256 milimoles of Sodium Carbonate are in the flask

Step-by-step explanation:

The chemist adds 180mL of a 1.42M sodium carbonate solution.

Molarity is an unit of concentration in chemistry defined as the ratio between moles of solute (Sodium Carbonate, in this case) per liter of solution.

A 1.42M solution contains 1.42 moles of Sodium carbonate in 1L of the solution.

As you have 180mL = 0.180L, moles of sodium carbonate you have are:

0.180L × (1.42 moles Sodium Carbonate / 1L) = 0.2556 moles of sodium carbonate

1000milimoles are equal to 1mole. 0.2556 moles are:

0.2556 moles × (1000 milimoles / 1 mole) =

256 milimoles of Sodium Carbonate are in the flask