Question

Two long parallel wires are separated by 11 cm. One of the wires carries a current of 54 A and the other carries a current of 45 A. Determine the magnitude of the magnetic force on a 4.3 m length of the wire carrying the greater current.

Answer 1

Step-by-step explanation:

It is given that,

The separation between two parallel wires, r = 11 cm = 0.11 m

Current in wire 1,
`q_1=54\ A`

Current in wire 2,
`q_2=45\ A`

Length of wires, l = 4.3 m

We need to find the magnitude of the magnetic force on a 4.3 m length of the wire carrying the greater current. The magnetic force per unit length is given by :

`(F)/(l)=(\mu_o I_1I_2)/(2\pi r)\\\\F=(\mu_o I_1I_2l)/(2\pi r)\\\\F=(4\pi * 10^(-7)* 54* 45* 4.3)/(2\pi * 0.11)\\\\F=0.0189\ N`

So, the magnetic force on a 4.3 m length of the wire on both of currents is F=0.0189 N.