Question

A closely wound, circular coil with radius 2.50 cmcm has 740 turns. Part A What must the current in the coil be if the magnetic field at the center of the coil is 0.0760 TT?

Answer 1

The current in the coil is 4.086 A

Step-by-step explanation:

Given;

radius of the circular coil, R = 2.5 cm = 0.025 m

number of turns of the circular coil, N = 740 turns

magnetic field at the center of the coil, B = 0.076 T

The magnetic field at the center of the coil is given by;

`B = (N\mu_o I)/(2R)`

where;

μ₀ is permeability of free space = 4 x 10⁻⁷ m/A

I is the current in the coil

R is radius of the coil

N is the number of turns of the coil

The current in the circular coil is given by

`B = (N\mu_o I)/(2R) \\\\I = (2BR)/(N\mu_o) \\\\I =(2*0.076*0.025)/(740*4\pi*10^(-7)) \\\\I = 4.086 \ A`

Therefore, the current in the coil is 4.086 A