Question

The maximum velocity of a particle executing simple harmonic motion with amplitude 7.0 mm is 4.4 m/s. The period of oscillation is? A. 0.5 s B. 0.1 s C. 100 s D. 0.01 s E. 10 s Reset Selection

Answer 1

D. 0.01 s

Step-by-step explanation:

The maximum speed is the amplitude times the angular frequency.

v = Aω

4.4 m/s = (0.0070 m) ω

ω = 628.6 rad/s

The period is:

ω = 2π / T

T = 2π / ω

T = 2π / (628.6 rad/s)

T = 0.01 s