Answer:
![N_2~+~3H_2~+~4O_2~->~2HNO_3~+~2H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/xvc43yw71gflt1opg8nbr5z74ywkc9eojg.png)
Step-by-step explanation:
We can start with the reaction of hydrogen and nitrogen to produce ammonia, so:
![N_2~+~H_2~->~NH_3](https://img.qammunity.org/2021/formulas/chemistry/college/1ldwlnu8b0cxsznveet5zelaaga33ny25z.png)
When we balance the reaction we will obtain:
![N_2~+~3H_2~->~2NH_3](https://img.qammunity.org/2021/formulas/chemistry/college/9rn6pemipvt8w9e4r9io83baua2i1y0zxt.png)
Now, the production of nitric acid with oxygen would be:
![NH_3~+~O_2~->~HNO_3~+~H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/ziis19cdevibueo8b34gx53rhr2hjhvuoi.png)
If we balance the reaction we will obtain:
![NH_3~+~2O_2~->~HNO_3~+~H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/7l76j5wyd40nzfdoh3yrwjed1qjovc11sb.png)
Now, if we put the reactions together we will obtain:
![N_2~+~3H_2~->~2NH_3](https://img.qammunity.org/2021/formulas/chemistry/college/9rn6pemipvt8w9e4r9io83baua2i1y0zxt.png)
![NH_3~+~2O_2~->~HNO_3~+~H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/7l76j5wyd40nzfdoh3yrwjed1qjovc11sb.png)
We can multiply the second reaction by "2":
![N_2~+~3H_2~->~2NH_3](https://img.qammunity.org/2021/formulas/chemistry/college/9rn6pemipvt8w9e4r9io83baua2i1y0zxt.png)
![2NH_3~+~4O_2~->~2HNO_3~+~2H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/32ljnwk3ujs7yik5p4sgo8m4q4bhxr9f0j.png)
We have "
" on both sides. In the first reaction is in the right in the second reaction is on the left. Therefore we can cancel out this compound and we will obtain:
![N_2~+~3H_2~+~4O_2~->~2HNO_3~+~2H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/xvc43yw71gflt1opg8nbr5z74ywkc9eojg.png)
On this reaction, we will have 2 nitrogen atoms on both sides, 6 hydrogen atoms on both sides, and 8 oxygen atoms on both sides. So, this would be the net reaction for the production of nitric acid.