Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=-6+(n-1)(1/5) A)-6,-5 1/5, -4 B)5, -5 1/5,1 4/5 C)-6, -5 2/5, -4 1/5 D) 0, 3/5, 1 4/5

Answer 1

the answer in C)-6, -5 2/5, -4 1/5

Answer 2

Explanation:

An arithmetic sequence is given by relation as follows :

`A(n)=-6+(n-1)(1)/(5)`

For the first term, put n = 1. So,

`A(1)=-6+(1-1)(1)/(5)\\\\A(1)=-6`

For fourth term, put n = 4. So,

`A(4)=-6+(4-1)(1)/(5)\\\\A(4)=(-27)/(5)\\\\A(4)=-5(2)/(5)`

For tenth term, put n = 10. So,

`A(10)=-6+(10-1)(1)/(5)\\\\A(10)=-6+(9)/(5)\\\\A(10)=(-21)/(5)\\\\A(10)=-4(1)/(5)`

Hence, the correct option is (C).