Question

A straight wire of length 0.56 m carries a conventional current of 0.4 amperes. What is the magnitude of the magnetic field made by the current at a location 2.6 cm from the wire

Answer 1

The magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.

Step-by-step explanation:

Given;

length of the straight wire, L = 0.56 m

conventional current, I = 0.4 A

distance of magnetic field from the wire, r = 2.6 cm = 0.026 m

To determine magnitude of magnetic field made by current in the wire, we will apply Bio-Savart Law;

`B = (\mu_o)/(4\pi r) (LI)/(√(r^2 +(L/2)^2) ) \\\\B = (4\pi *10^(-7))/(4\pi *0.026) (0.56*0.4)/(√((0.026)^2 +(0.56/2)^2) )\\\\B = 3.846*10^(-6)(0.7966)\\\\B = 3.064*10^(-6) \ T`

Therefore, the magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.