Greetings from Brasil...
Here we don't have much to go
∛Y = A.(C + 1/X)
∛Y = (AC + A/X)
raising both members to the cube.....
(∛Y)³ = (AC + A/X)³
from Notable Products: (a + b)³ = a³ + 3a²b + 3ab² + b³
Y = (AC)³ + 3(AC)².(A/X) + 3AC(A/X)² + (A/X)³
Y = A³[C³ + (3C²/X) + (3C/X²) + (1/X³)]