148k views
0 votes
"What is the energy density (energy per cubic meter) carried by the magnetic field vector in a small region of space in a EM wave at an instant of time when the electric vector is a maximum of 3500V/m

User Ozanmuyes
by
7.6k points

1 Answer

2 votes

Answer:

The energy density is
Z = 5.4 2 *10^(-5 ) \ J/m^3

Step-by-step explanation:

From the question we are told that

The electric vector is
E = 3500 \ V/m

Generally the energy vector is mathematically represented as


Z = 0.5 * \epsilon_o * E^2

Where
\epsilon_o is the permitivity of free space with the value
\epsilon_o = 8.85*10^(-12) \ \ m^(-3) \cdot kg^(-1)\cdot s^4 \cdot A^2

substituting values


Z = 0.5 * 8.85 *10^(-12) * 3500^2


Z = 5.4 2 *10^(-5 ) \ J/m^3

User Pershawna
by
8.7k points