Question

A light ray in air strikes water at an angle of incidence equal to 40°. If the index of refraction for water is 1.33, what is the angle of refraction?

Answer 1

The angle of refraction is 28.68°

Step-by-step explanation:

Given data

angle of incidence, i=40°

angle of refraction,r = ?

index of refraction u= 1.33

applying the formula

`u=( sin i)/( sin r)`

According to Snell's law, the incident, normal and refracted rays all act on the same point.

Substituting and solving for r we have.

`1.33= (sin (40))/(sin (r)) \\\\sin(40)= 1.33* sin(r)\\\0.642= 1.33* sin(r)`

divide both sides by 1.33 we have

`sin(r)= (0.642)/(1.33) \\\sin(r)= 0.48\\\r= sin^-^10.48\\\r= 28.68`

r= 28.68°