Question

Suppose you have a tablet with a capacity of gigabytes. For a plain text​ book, one byte typically corresponds to one character and an average page consists of 2000 characters. Assume all gigabytes are used for plain text books. a. How many pages of text can the tablet​ hold? b. How many​ 500-page books can the tablet​ hold?

Answer 1

a. 17,500,000 pages

b. 35,000

Step-by-step explanation:

The computation is shown below:

As we know that

`1 giga\ bytes = 1 * 10 ^ {9} bytes`

So for 35 gigabytes it would be

`= 35 * 10 ^ {9} bytes`

And it is given that there is 2,000 characters

a. So the number of text pages would be

Let us assume that

for 2,000 it would be 1 page

So for
`35 * 10 ^ {9} bytes` it would be x

Now we solve the x which is equal to

`= \frac {35 * 10 ^ {9} bytes}{2,000}`

= 17,500,000 pages

b. Now for 500 pages, it would be

`= (17,500,000)/(500)`

= 35,000