Question

22.

Makes s the subject

`√(p) \: is \: equals \: to \: \sqrt[r]{w \: - as ^(2)}`
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Answer 1

Explanation:

`√(p) = \sqrt[r]{w - {as}^(2) }`

Find raise each side of the expression to the power of r

That's

`( √(p) )^(r) = (\sqrt[r]{w - {as}^(2) } ) ^(r)`

we have

`( √(p) )^(r) = w - {as}^(2)`

Send w to the left of the equation

`( √(p) )^(r) - w = -{as}^(2)`

Divide both sides by - a

We have

`{s}^(2) = -(( √(p) )^(r) - w)/(a)`

Find the square root of both sides

We have the final answer as

`s = \sqrt{ -(( √(p) )^(r) - w )/(a) }`

Hope this helps you