Question

A force of 3300 N is exerted on a piston that has an area of 0.060 m².

What force is exerted on a second piston that has an area of 0.18 m??

Answer 1

9,900 N

Step-by-step explanation:

We know that the pressure in a fluid is transmitted with an equal pressure throughout, hence the formula
`pressure_1` =
`pressure_2`. As your know pressure is represented by force over area, so this formula can be rewritten as
`force_1/Area_1` =
`force_2/Area_2` .

3300 N / 0.060 m² =
`force_2` / 0.18 m²

Let's say that
`force_2` = x. Now let us solve for x.

3300 N / 0.060 m² = x / 0.18 m²,

3300 / 0.060 = x / 0.18,

55,000 = x / 0.18,

x = 55,000
`*` 0.18 = 9,900 N - this is the force exerted on the second piston