23.4k views
0 votes
What is the equation of a circle with the center of (2,3) and crosses through the point (2,1)​

1 Answer

4 votes

Answer: (x - 2)² + (y - 3)² = 4

Explanation:

The equation of a circle is: (x - h)² + (y - k)² = r² where

  • (h, k) is the center of the circle
  • r is the radius of the circle.

Given: (h, k) = (2, 3) and (x, y) = (2, 1)

Input those values to find r²:

(x - h)² + (y - k)² = r²

(2 - 2)² + (1 - 3)² = r²

0 + 4 = r²

4 = r²

Now input (h, k) = (2, 3) and r² = 4 into the equation of a circle:

(x - h)² + (y - k)² = r²

(x - 2)² + (y - 3)² = 4

User Sandun Harshana
by
5.8k points