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X^2-y^2=3y in polar form

User Tomek
by
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1 Answer

1 vote

Answer:

Explanation:

put x=r cos θ

y=r sin θ

r²cos²θ-r²sin²θ=3rsin θ

r²(cos²θ -sin²θ)=3r sin θ

r²cos 2θ=3rsinθ

r cos 2θ=3 sin θ

r=3sec 2θ sin θ

User Emarref
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