Find the focus. y= -1/12 (x)² - 6

Question

asked Mar 6, 2021 115k views

1 Answer

Melva · Answer 1 · 2021-03-12T06:24:12+0000

Answer:

$\Large \boxed{\sf\ \ (0,-9) \ \ }$

Explanation:

Hello,

We know that when the parabola equation is

y=a(x-h)^2+k

the vertex is (h,k) and the focus is

(h,k+(1)/(4a))

Here, the equation is

y=-(1)/(12)x^2-6

so

$a=-(1)/(12)\\\\h = 0\\\\k =-6$

So,

k+(1)/(4a)=-6-(12)/(4)=-6-3=-9

Then, the focus is

$\large \boxed{\sf\ \ (0,-9) \ \ }$

I attached the graph, included the focus so that you can see it :-)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you