Question

Find the partial sum of the first 4 terms of the series:

5n + 2
n=1
60
58
85
None of these

Answer 1

`\large \boxed{\sf \ \ \sum_(n=1)^(n=4) (5n + 2) = 58 \ \ }`

Explanation:

Hello,

We need to compute the following:

`\displaystyle \sum_(k=1)^(k=4) (5\cdot k + 2)= (5*1+2) + (5*2+2)+ (5*3+2) + (5*4+2)\\\\=7 + 12 + 17 + 22 = 19 + 39 = 58`

Hope this helps.

Do not hesitate if you need further explanation.

Thank you