Answer:
5
4
1
3
Step-by-step explanation:
In D-glucose, there is an aldehyde functional group, and the carbonyl group is at carbon 1 when looking at the Fischer projection.
In D-Fructose, there is a ketone functional group, and the carbonyl group is at carbon 2 when looking at the Fischer projection.
Both of your questions say "glucose" so I gave you my answer to the best of my understanding which required me to change the second answer to FRUCTOSE.